[英]Converting Guzzle response t Laravel models
I am trying to get data from a json api and the convert the returned array into a collection of models. 我正在尝试从json api获取数据并将返回的数组转换为模型的集合。 so the api returns back an array of users with a id and name field.
因此api返回具有id和name字段的用户数组。 When I convert the json to models I get the correct number of elements but all the attributes in the model are null.
当我将json转换为模型时,我得到了正确数量的元素,但是模型中的所有属性均为null。
I tried using bothe the hydrate and fill on the model to convert the json into models. 我尝试同时使用水合物和填充模型以将json转换为模型。
$client = new Client(); //GuzzleHttp\Client
$request = new \GuzzleHttp\Psr7\Request('GET', 'https://test.com/users');
$json = $client->sendAsync($request)->then(
function ($response) {
return $response->getBody()->getContents();
}, function ($exception) {
return $exception->getMessage();
}
)->wait();
$object = (array)json_decode($json);
$collection = User::hydrate($object);
return UserResource::collection($collection);
class UserResource extends JsonResource
{
public static $wrap = null;
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->name,
'name' => $this->nameCombo,
];
}
}
When the call is finished the controller returns back 通话结束后,控制器返回
{"data":[{"id":null,"name":null},{"id":null,"name":null}]} {“ data”:[{“ id”:null,“ name”:null},{“ id”:null,“ name”:null}]}
The json returns back ids and names that are not null json返回不为null的id和名称
I am testing this code and works just fine: 我正在测试此代码,并且工作正常:
$client = new Client(); //GuzzleHttp\Client
$request = new \GuzzleHttp\Psr7\Request('GET', 'https://jsonplaceholder.typicode.com/users');
$json = $client->sendAsync($request)->then(
function ($response) {
return $response->getBody()->getContents();
}, function ($exception) {
return $exception->getMessage();
}
)->wait();
$object = (array)json_decode($json);
$collection = User::hydrate($object);
return UserResource::collection($collection);
class UserResource extends JsonResource
{
public static $wrap = null;
/**
* Transform the resource into an array.
*
* @return array
*/
public function toArray()
{
return [
'id' => $this->id,
'name' => $this->name,
];
}
}
Are you sure this part is correct? 您确定这部分正确吗?
return [
'id' => $this->name,
'name' => $this->nameCombo,
];
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