如何确定C ++中的向量维？

Question

In python, I got a list 'quad_list = ((len(D),4,2))' , and 'len(D)' is a 2 dimension list something like ' [[0,1,2,3],[1,2,3,4],[3,4,5,6]]' . Then if I want a same list in C++, that 'quad_list' going to be 'std::vector<std::vector<std::vector<int>>> quad_list(D.size(),4,2)' ? so it is a 3 dimension vector, and what if I wanna insert some value to the vector, or just do something like 'for i, j in zip(D, range(len(D))):' this python code in C++.... how to traversing the list in C++...

I think if i wanna traversing the three dimension vector in C++, it as same as print, so it should be three level loop..and like

for(int i; i < vector...emmmmmm; i++)
{
    for(int j; j< vector.....emmmm; j++)
    {
        for(int k; k < vector......; k++)
        {
            ....
        }
    }
}

have no idea...sorry

std::vector<std::vector<double>> D = region_group(region_list);
int lend = D.size();
std::vector<int> N(2, 0);
std::vector<std::vector<int>> qua(4, N);
std::vector<std::vector<std::vector<int>>> quad_list(lend, qua);//quad_list((len(D),4,2))
std::vector<int> S(4, 0);
std::vector<std::vector<int>>score_list(lend, S); //score_list = np.zeros((len(D), 4))

here for the code python for group,g_th in zip(D,range(len(D))):

Please give me some hints about the operation of high dimension vector in C++.

Answer 1

If you have access to boost and C++17 , it's very similar to python

for i, e in enumerate(C): # more pythonic than zip(range(len(C)), C)
    ...

Becomes

using boost::adaptors::index;
for (auto [i, e] : index(C))
{
    ...
}

If you really want to have something similar to zip(C, range(len(C)))

for (auto [i, e] : boost::combine(boost::irange(C.size()), C))