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在Javascript中使用PHP二维数组

[英]Using PHP two dimensional Array in Javascript

in php I have this array 在PHP中我有这个数组

$MAtoJS[] = array('Max','Mustermann','N','A80');
$MAtoJS[] = array('Michaela','May','N','A78');
$MAtoJS[] = array('Hans','Gerstelhuber','N','M12');
$MAtoJS[] = array('Alfred E.','Neumann','N','T25');
$MAtoJS[] = array('James','Bond','N','M72');

Still in the php part I prepare the array for js 仍然在php部分中,我为js准备了数组

$MAarrayForJS = json_encode(json_encode($MAForJS));

In the javascript part I create a js-array 在javascript部分中,我创建了一个js-array

var MAarray = new Array(<?php echo $MAarrayForJS; ?>); alert(MAarray)

The content of MAarray is MAarray的内容是

[["Max","Mustermann","N","A80"],["Michaela","May","N","A78"],["Hans","Gerstelhuber","N","M12"],["Alfred E.","Neumann","N","T25"],["James","Bond","N","M72"]]

using 运用

console.log(MAarray[0]);

I tried to get for example the first name of Hans by this code 我试图通过此代码获取例如汉斯的名字

var FirstName = MAarray[0][2][1];

which results in "undefined" in the console.log. 在console.log中导致“未定义”。

How can I access to a specific value in a specific array, in this case to set the var FirstName to the value "Hans" from the third "subarray"? 我如何访问特定数组中的特定值,在这种情况下,如何将第三个“子数组”中的var FirstName设置为值“ Hans”?

Are you looking for this... ? 您在寻找...吗?

$MAtoJS = [];

$MAtoJS[] = array('Max','Mustermann','N','A80');
$MAtoJS[] = array('Michaela','May','N','A78');
$MAtoJS[] = array('Hans','Gerstelhuber','N','M12');
$MAtoJS[] = array('Alfred E.','Neumann','N','T25');
$MAtoJS[] = array('James','Bond','N','M72');

$MAarrayForJS = json_encode($MAtoJS);

?>

<script>
    var MAarray = <?php echo $MAarrayForJS; ?>;
    console.log(MAarray[0][0]); // Max
</script>

Please note that the array is 2 dimensional and not 3 dimensional you're accessing the 3rd dimension which will always yield undefined, have a look at below code snippet in which the value is fetched, altered as per the requirement: 请注意,数组是2维的,而不是3维的,您正在访问第3维,它将始终产生未定义的状态,请查看下面的代码片段,在其中提取了值,并根据要求进行了更改:

 let MAarray = [["Max","Mustermann","N","A80"],["Michaela","May","N","A78"],["Hans","Gerstelhuber","N","M12"],["Alfred E.","Neumann","N","T25"],["James","Bond","N","M72"]]; console.log(MAarray[2][0]); MAarray[2][0] = "New Name"; console.log(MAarray[2][0]); 

For some reason you are using json_encode 2 times. 由于某种原因,您使用json_encode 2次。 You only need to use it once. 您只需要使用一次。

Change following 更改以下

$MAarrayForJS = json_encode(json_encode($MAForJS));

To

$MAarrayForJS = json_encode($MAtoJS);

Then in the JS you can use console.log(MAarray[0][2][1]); 然后在JS中可以使用console.log(MAarray [0] [2] [1]);

Try 尝试

var FirstName = MAarray[2][1];

It seems like you are trying to access the third level of a two dimensional array. 似乎您正在尝试访问二维数组的第三级。

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