以两个包含单词的列表作为输入，以形成包含两个单词的元组，每个列表中的一个单词的起始字母相同

Question

I've to take two lists as an input which contain words. Using those words I form a tuple using two words, one from each list that contain the same first letter of each word. Then creating a list of those tuples and printing them.

I have a solution, however, I cannot seem to produce the same item twice. Here's an example of what I mean in words.

List A: ['Jack', 'Tim', 'John', 'Ahmed']

List B: ['Julie', 'Tom', 'Henry', 'Harper']

c = input().lower()
d = input().lower()

a = c.split()
b = d.split()

x = []
for i in range(len(a)):
    if a[i][0] == b[i][0]:
        x.append((a[i], b[i]))

print(x)

My Output: [('joy', 'juggle'), ('troy', 'trim')]

Expected Output: [('Jack', 'Julie'), ('John', 'Julie'), ('Tim', 'Tom')]

I'm quite new to learning the language and wasn't quite able to find any similarities to my previous work to find out how I could reiterate through a / b without reproducing the same output.

Answer 1

Use itertools.product to get all the pairs and then filter them out:

In [1]: from itertools import product

In [2]: a =  ['Jack', 'Tim', 'John', 'Ahmed']

In [3]: b = ['Julie', 'Tom', 'Henry', 'Harper']

In [4]: out = [i for i in product(a, b) if i[0][0] == i[1][0]]

In [5]: out
Out[5]: [('Jack', 'Julie'), ('Tim', 'Tom'), ('John', 'Julie')]

Answer 2

With list comprehensions:

In [50]: a = ['Jack', 'Tim', 'John', 'Ahmed']

In [51]: b = ['Julie', 'Tom', 'Henry', 'Harper']

In [55]: c = [(x,y) for x in a for y in b if x.lower()[0]==y.lower()[0]]

In [56]: c
Out[56]: [('Jack', 'Julie'), ('Tim', 'Tom'), ('John', 'Julie')]

Answer 3

你可以试试这个

[(x, y) for x in A for y in B if x[0] == y[0]]