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如何通过文件条目获取要上传的文件的路径?

[英]How do I get the path of a file I want to upload by a file entry?

I want to upload a file by a file entry and then when I click on "Save" I want to get the path of this selected file. 我想通过文件条目上传文件,然后单击“保存”时,我要获取此选定文件的路径。

The next step would be to create either a .txt or a yaml file with this path in it as output. 下一步将是创建一个.txtyaml文件,并在其中将此路径作为输出。

Could someone help me with this? 有人可以帮我吗?

win.addFileEntry("InputFile")
def press(button):
    if button == "Exit":
        win.stop()
    if button == "Save":
        print(path._getfullpathname(__file__))
        print("Saved!")

win.addButtons(["Add", "Remove", "Save", "Load", "Exit"], press)

您只需要向FileEntry询问其内容: filename = win.getEntry('InputFile')

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