如何根据最小日期和其他条件（其中每个事务在SQL中可以具有多个日期）过滤记录？

Question

I want to extract transaction where quantity is -1 on very first date of the same transaction. Assume that single transaction have multiple rows.

We have following table

tXid_ID     Date        Qty
---------------------------------------
1       1/2/2014    -1
2       2/3/2014    1
2       3/3/2014    1
3       4/3/2014    1
4       5/3/2014    -1
4       6/3/2014    1
5       7/3/2014    -1
5       8/3/2014    1
6       9/3/2014    1
7       10/3/2014   1
7       11/3/2014   -1
----------------------------------

All I want to extract only those transactions which do not have quantity -1 on its first entry within same transaction ID.

Expected results should be like this

tXid_ID     Date        Qty
---------------------------------------
2       2/3/2014    1
2       3/3/2014    1
3       4/3/2014    1
6       9/3/2014    1
7       10/3/2014   1
7       11/3/2014   -1
----------------------------------

Answer 1

try like below using subquery

 select a.* from table_name a
 where tax_id not in (  select tax_id from table_name t1
    where t1.date= (select min(date) from 
                table_name t2 where t1.tax_id=t2.tax_id
               ) and  t1.qty=-1
)

Answer 2

this one should work

select
  *
from
  tbl
where
  tXid_ID in (
    select
      t.tXid_ID
    from
      tbl t
      inner join (
        select
          min(date) as minDate,
          tXid_ID
        from
          tbl
        group by
          tXid_ID
      ) t1 on t1.minDate = t.date
    where
      t.Qty != -1
  )

Answer 3

I think the simplest method is aggregation:

select txid_id
from t
group by txid_id
having min(date) = min(case when qty = -1 then date end);

The having clause simply says that the minimum date is the minimum of the date where qty = -1 .