Scala中的Curry函数

Question

I am new to Scala and I just started learning it and now trying some exercises. This one in particular I have a trouble understanding.

I understand up to the (f: (A, B) => C) part, but the rest I dont quite get it. Can someone please explain what's happening after the anonymous function part?

Thanks!

This is the function:

def curry[A, B, C](f: (A, B) => C): A => (B => C) = a => b => f(a, b)

Answer 1

• def curry a method named "curry"
• [A, B, C] will deal with 3 different types
• (f it will receive an argument that we'll name "f"
• : (A, B) => C) that argument is type "function that takes A,B and returns C"
• : A => (B => C) "curry" returns type "function that takes A and returns function that takes B and returns C"
• = here's the "curry" code
• a => b => f(a, b) function that takes an argument (we'll call "a") and returns a function that takes an argument (we'll call "b") that returns the value returned after "a" and "b" are passed to "f()"