如何避免每次编译时都必须键入 -std=c++11

Question

SOLUTION : I used the solution by Sander De Dycker and just updated my gcc version, which worked perfectly.

First, I want to point out that I don't know anything about CMake or shell scripts.

What is the best way to avoid having to type -std=c++11 each time when compiling a C++ file?

(eg g++ -std=c++11 file.c).

• I found a solution online, but it didn't seem to work or I didn't know how to use it properly:

  https://github.com/openalpr/openalpr/issues/528

  Put this line :

  set(CMAKE_CXX_FLAGS "${CMAKE_CXX_FLAGS} -std=c++11")

  after the first line of CMakeLists.txt located in src directory

  This CMakeLists.txt file didn't exist, so I just created it. This might've been a first mistake. Moreover, my assumption was that then I could just type g++ file.c , but maybe I have to type something else instead?

• My supervisor told me that the most efficient way was to use a shell script , which I am not familiar with. Any suggestions for this method?

Answer 1

CMakeLists.txt is the rule file build your project, gcc is one compiler.

1. create a CMakeLists.txt in your dir.

cmake_minimum_required(VERSION 3.0)
project(project_name)
# use c++ 11
set(CMAKE_CXX_STANDARD  11)
add_executable(func file.cpp)

2. create folder named build , and cd build
3. build it

cmake ..
make

4. finaly, you'll get execute file named func .

you should learn about CMake or Make https://cmake.org/cmake-tutorial/

Answer 2

An even simpler option is stick your defaults in a Makefile :

CPPFLAGS += -std=c++11 -Wall -Wextra -pedantic -Wshadow

Then you can just call make file and Make will compile file.cpp into an executable file for you.