如何在python中忽略嵌套json值的父级（如果不存在）？

Question

I'm trying to extract the value y that sometimes is nested and sometimes is not. I use code like this:

address = response.json()[x][y]

I also use a ternary operation on x like:

address = response.json()[x if condition else ""][y]

It works when y is a nested value of x , but when it's not I get the error KeyError: '' . I also tried None instead of "" , but still the same error KeyError: None . Also have tried this:

address = response.json()[x] if condition else ""[y]

I'd like to keep it compact if possible. Thanks in advance.

Answer 1

Safe and short way with dict.get(key[, default]) function:

data = response.json()
address = data.get('y') or data.get('x', {}).get('y')

Answer 2

Not best code, but should afford your problem

try:
    address = response.json()[x][y]
except:
    address = response.json()[y]