Gulp错误：您是否忘记了异步完成信号？

Question

Problems with compiling what I see as a simple script using gulp. When ran it causes a "Did you forget to signal async completion?" error.

Looking at the internet this seems to be a problem with async functions and read that passing and adding the done function would resolve this. In my case this isn't the case so wondering what else I'm doing wrong.

gulp.task("compile-less", done => {
  gulp
    .src("./app/design/frontend/Playsports/theme_frontend_base/web/css/_base.less")
    .pipe(less())
    .pipe(
      gulp.dest(() => {
        return "./pub/static/frontend/Playsports/gcn/en_GB/css/";
      })
    );
  done();
});

gulp.task("default", done => {
  gulp.series("compile-less");
  done();
});

I would expect this to not error and complete the task.

Answer 1

This would be the general form:

gulp.task("default", gulp.series("compile-less", done => {
  // do something else here
  done();
}));

In your case I believe this is sufficient:

gulp.task("default", gulp.series("compile-less"));