PHP preg_match_all仅匹配最后一个元素

Question

I've this regex

{{([ a-zA-Z0-9_\-]+)\s*(?:\[([ a-zA-Z0-9_\-]+)\]\s*)*}}

and i need to match strings such as:

{{word with spaces}}
{{word with spaces [sub1]}}
{{word with spaces   [sub1]  [sub 2]  [Sub-3] }}

capturing word with spaces , and sub1 , sub 2 , Sub-3 .

The regex is working but the for the sub-s string matching gives only the last match, ie Sub-3 . How to get all sub1 , sub 2 , Sub-3 ? Thanks

Answer 1

Here is another variant using \\G that is bit faster and avoids empty matches:

(?:{{([\w-]+(?:\h+[\w-]+)*)|(?!\A)\G)(?:\h*\[([^]]+)]|\h*}})

RegEx Demo

\\G asserts position at the end of the previous match or the start of the string for the first match.

Answer 2

To get the value for sub in mulitple times group 2 you might use \\G to assert the position at the end of the previous match:

(?:{{([\w-]+(?: [\w-]+)*)|\G(?!$))(?:\h+\[([^]]+)\])?(?=.*})

Regex demo