简体   繁体   English

在flask-pymongo中创建身份验证子用户

[英]create authentication sub-user in flask-pymongo

I've a flask web app in which I authenticate to the "core" DB as admin. 我有一个Flask Web应用程序,在该应用程序中,我以管理员身份验证了“核心”数据库。

MONGO_URI = "mongodb://myUserAdmin:abc123@localhost:27017/test?authSource=admin"
mongo = PyMongo(app)
# ... and I am able to interact with the DB
    flash(mongo.db.user.find_one())

now, I want to create sub-DBs for each user of the app and let him modify only its specific DB (or table). 现在,我想为该应用程序的每个用户创建子数据库,并让他仅修改其特定的数据库(或表)。 How can I configure flask to manage that? 如何配置flask来管理它? I tried to look in web but found no solutions. 我试图查看网络,但没有找到解决方案。

Thanks in advance for any help! 在此先感谢您的帮助!

You can do something like this 你可以做这样的事情

Create Authentication middleware 创建身份验证中间件

class UserAuthenticationMiddleware:

    def __init__(self, app):
        self.app = app

    def __call__(self, environ, start_response):
        '''
            Authenticate the user here
        '''
        self.app.user = {'_id': ObjectId('ddddddddssssssssssss')} #  authenticate the user and get it from db
        return self.app(environ, start_response)

Then create a Database middleware to get a db for the user 然后创建数据库中间件为用户获取数据库

class DbMiddleware(object):
    def __init__(self, app):
        self.app = app

    def __call__(self, environ, start_response):
        if hasattr(self.app, 'user'):

            # create a database by user id or you can use any unique field here
            self.app.db = self.app.db_client[str(self.app.user._id)]
        else:
            self.app.db = self.app.db_client['default_db']
        return self.app(environ, start_response)

Then in create app instance 然后在创建应用程序实例

from flask import Flask


if __name__ == '__main__':
    app = Flask(__name__)
    app.db_client = MongoClient() 
    app = DbMiddleware(UserAuthenticationMiddleware(app))
    app.run()

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM