如何按键对json文件排序

Question

I have a json file, for example,

{
"2":{"name": "A", "Label": "Student"}, 
"3":{"name": "B", "Label": "Student"}, 
"1":{"name": "B", "Label": "Student"}, 
...
}

I want to sort the file by keys, then the result should be:

"1":{"name": "B", "Label": "Student"}, 
"2":{"name": "A", "Label": "Student"}, 
"3":{"name": "B", "Label": "Student"}, 
...
}

How can I achieve it?

Answer 1

Try this, if you want it as JSON

import json    
json.loads(json.dumps(values, sort_keys=True))

Output

{"1": {"Label": "Student", "name": "B"}, "2": {"Label": "Student", "name": "A"}, "3": {"Label": "Student", "name": "B"}}

Answer 2

d = {
"2":{"name": "A", "Label": "Student"},
"3":{"name": "B", "Label": "Student"},
"1":{"name": "B", "Label": "Student"},
}

import json
from collections import OrderedDict

print(json.dumps(OrderedDict(sorted(d.items())), indent=4))

Prints:

{
    "1": {
        "name": "B",
        "Label": "Student"
    },
    "2": {
        "name": "A",
        "Label": "Student"
    },
    "3": {
        "name": "B",
        "Label": "Student"
    }
}

EDIT: If your keys are integers encoded as string and you want to sort them ascending:

print(json.dumps(OrderedDict(sorted(d.items(), key=lambda k: int(k[0]))), indent=4))