正则表达式在数组中查找值

Question

Here is my JavaScript with a RegExp which does not work, I cannot find the correct syntax:

var arr = ['111', '222|12', '333'];
new RegExp('\\b' + value + '\\b').test(arr);
value = '111'; //true
value = '222'; //true
value = '12'; //true

I need avoid numbers following a | , meaning that a test with number 12 should return false. So values 111, 222 and 333 must yield true only.

I just know that the first \\\\b must be replaced with a syntax to avoid the | character.

Answer 1

You are passing an array to the test method, while it expects a string. So the array gets coerced to a comma separated string "111,222|23,333". Obviously that makes your tests succeed, but you would also get a match with "111,222".

Using a regular expression for this seems overkill. You can use split("|") to get rid of the part that follows a pipe symbol, and then just do an equality test on each remaining value. Use the some method to iterate until you get such a match:

 function isMatch(arr, value) { return arr.some(s => s.split('|')[0] === value); } var arr = ['111', '222|12', '333']; console.log(isMatch(arr, '111')); //true console.log(isMatch(arr, '222')); //true console.log(isMatch(arr, '333')); //true console.log(isMatch(arr, '12')); //false