Laravel-将请求重定向到外部URL并返回其响应作为响应

Question

i'm building an app using Laravel for providing some API for an android application, and i'm using some external APIs from another server (with another URL). i want to make something like proxy or tunnel for external API requests from android side but in my own URL.

for example: android wants to request for externalUrl.com/api/objects but i want he request to this myDOmain.com/api/x/objects and get the exact same response that the first link returns, without any change. and there is more than one external API, and i don't want to write separate code for each one.

need something like this :

Route::any('/x/{somewhere}', function($request){
return [$request, externalUrl.com/api/{somewhere}]->response;
})

---

i'm not asking for http request libraries! i want to redirect request to another domain and return its request.

Answer 1

You can use Guzzle :

use Guzzle\Http\Client;
use Guzzle\Stream\PhpStreamRequestFactory;
[...]
$request = new Client("externalUrl.com/api/{$somewhere}");

$response = $request->send();
return $response->getBody();

Answer 2

Best option is to install Guzzle. https://github.com/guzzle/guzzle

It's really simple to use it.

$client = new \GuzzleHttp\Client();
$response = $client->request('GET', 'externalUrl.com/api/{somewhere}');

return $response->getBody();