如何使用“ REGEXP”运算符实现“ LIKE'％a％a％'”

Question

Consider the following line to search for strings using the LIKE operator:

LIKE '%a%a%'

This returns when the selected string has two or more instances of the letter 'a' in the string. How can I use REGEXP operator to only match a string with two instances of the letter a , no more and no less?

I have tried to read the documentation but I can't wrap my head around the descriptions for the symbols used in regular expressions

Answer 1

Try this:

^([^a]*a){2}[^a]*$

Here is Demo