矩阵中第一行的元素，每行取一个元素，并与行的所有元素进行迭代

Question

Consider a 2D list in python. Taking the first list of given 2D list, I want to do XOR operation of each element from the first list with one element each from subsequent lists so that I have n-1 elements operated with that one element.

Example - list = [[0,1], [0,1,2,3], [0,1,2]]

combinations formed will be - 0^0^0, 0^0^1, 0^0^2, 0^1^0, 0^1^1, 0^1^2, 0^2^0, 0^2^1, 0^2^2, 0^3^0, 0^3^1, 0^3^2, 1^0^0, 1^0^1, 1^0^2, 1^1^0, 1^1^1, 1^1^2, 1^2^0, 1^2^1, 1^2^2, 1^3^0, 1^3^1, 1^3^2

condition - The size of any of the list or sublists is not predefined

Answer 1

for_the_product = [[0,1], [0,1,2,3], [0,1,2]]
for one_tuple in itertools.product(*for_the_product):
    do_something_with(one_tuple)

More explanation in the python documentation . The * gives each elements of your initial list ( for_the_product in my code) as an argument to the product function.