[英]One to many relation in Entity Framework Core
I have two tables News
and Comments
. 我有两个表
News
和Comments
。 The Comments
table has two foreign key columns UserId
and NewsId
. Comments
表具有两个外键列UserId
和NewsId
。
When I get a News
item by id in Entity Framework Core, comments are null. 当我在Entity Framework Core中按ID获取
News
项时,评论为null。
News model class: 新闻模型类:
public partial class News
{
public News()
{
NewsComments = new HashSet<NewsComments>();
NewsLikes = new HashSet<NewsLikes>();
}
public int Id { get; set; }
public string Title { get; set; }
public string Text { get; set; }
public string Thumbnail { get; set; }
public string Image { get; set; }
public DateTime? Date { get; set; }
public int CategoryId { get; set; }
public int PublisherId { get; set; }
public int? ViewCount { get; set; }
public int? LikeCount { get; set; }
public int? CommentCount { get; set; }
public virtual NewsCategories Category { get; set; }
public virtual NewsPublishers Publisher { get; set; }
public virtual ICollection<NewsComments> NewsComments { get; set; }
public virtual ICollection<NewsLikes> NewsLikes { get; set; }
}
Comments model class: 评论模型类:
public partial class NewsComments
{
public int Id { get; set; }
public int UserId { get; set; }
public int NewsId { get; set; }
public string Text { get; set; }
public DateTime? Date { get; set; }
public bool? IsAccept { get; set; }
public virtual News News { get; set; }
public virtual Users User { get; set; }
}
Get news method: 获取新闻方法:
public News GetNews(int id)
{
return _db.News.Find(id);
}
In EF if you are set by default with eager loading so you need to include the model property of the relationship like so : 在EF中,如果您默认设置为预先加载,那么您需要像下面这样包含关系的model属性:
public News GetNews(int id)
{
return _db.News.Include(n=>n.NewsComments).Find(id);
}
Unless you have have forced to lazy load but still you have to setup the relationship on the context 除非您被迫延迟加载,但仍然必须在上下文中设置关系
modelBuilder.Entity<NewsComments>(entity =>
{
entity.HasOne(nc => nc.News)
.WithMany(n => n.NewsComments)
.HasForeignKey(nc => nd.NewsId);
});
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