在 JSON 中验证多个节点？

Question

Here is my Json data

{
    "DateCreated": "2019-07-26T10:25:27.1326123Z",
    "CachedEntity": false,
    "ToolsTitle": null,
    "Profile": false,
    "MenuItems": [{
            "SubMenuItems": [{
                    "SubMenuItems": [],
                    "Title": "Sub Menu Item1",
                    "IsAuthorized": true,
                }, {
                    "SubMenuItems": [],
                    "Title": "Sub Menu Item2",
                    "IsAuthorized": true,
                }
            ],
            "Title": "Menu Item1",
            "IsAuthorized": true
        }, {
            "SubMenuItems": [{
                    "SubMenuItems": [],
                    "Title": "Sub Menu Item3",
                    "IsAuthorized": false,
                }, {
                    "SubMenuItems": [],
                    "Title": "Sub Menu Item4",
                    "IsAuthorized": true,
                }
            ],
            "Title": "Menu Item2",
            "IsAuthorized": true
        }
    ]
}

I need to verify values in MenuItems list.

eg IsAuthorized value is False for Sub Menu Item3 .

"Title": "Sub Menu Item3" , "IsAuthorized":false

Answer 1

You can select all SubMenuItems that satisfies: IsAuthorized = True with list comprehension:

out = [sub_menu_Items for sub in data["MenuItems"]
       for sub_menu_Items in sub["SubMenuItems"] if not sub_menu_Items["IsAuthorized"]]

print(out)
# [{'SubMenuItems': [], 'Title': 'Sub Menu Item3', 'IsAuthorized': False}]

# To match the expected output:
out = [{k: full_dict[k] for k in ('Title', 'IsAuthorized')} for full_dict in out]
print(out)
# [{'Title': 'Sub Menu Item3', 'IsAuthorized': False}]

If you need to load data from a .json file, you can use the following:

import json
from jsoncomment import JsonComment

with open("filename.json", "r") as f:
    parser = JsonComment(json)
    data = parser.load(f)

Note: The comma at the end of the list in the .json file is not supported by json.load() . One solution might be to use jsoncomment as suggested in this discussion .

Answer 2

You can use recursion with a generator:

data = {'DateCreated': '2019-07-26T10:25:27.1326123Z', 'CachedEntity': False, 'ToolsTitle': None, 'Profile': False, 'MenuItems': [{'SubMenuItems': [{'SubMenuItems': [], 'Title': 'Sub Menu Item1', 'IsAuthorized': True}, {'SubMenuItems': [], 'Title': 'Sub Menu Item2', 'IsAuthorized': True}], 'Title': 'Menu Item1', 'IsAuthorized': True}, {'SubMenuItems': [{'SubMenuItems': [], 'Title': 'Sub Menu Item3', 'IsAuthorized': False}, {'SubMenuItems': [], 'Title': 'Sub Menu Item4', 'IsAuthorized': True}], 'Title': 'Menu Item2', 'IsAuthorized': True}]}
def results(d):
   if "IsAuthorized" in d:
      yield {i:d.get(i) for i in ['Title', 'IsAuthorized']}
   for a, b in d.items():
      if isinstance(b, dict):
         yield from results(b)
      elif isinstance(b, list):
         for i in b:
            yield from results(i)

result = list(results(data))

To find instances when IsAuthorized is False :

final_results = [i for i in result if not i['IsAuthorized']]

Output:

[{'Title': 'Sub Menu Item3', 'IsAuthorized': False}]