打包多个python元组并排序

Question

Question: You are required to write a program to sort the (name, age, height) tuples by ascending order where name is string, age and height are numbers. The tuples are input by console. The sort criteria is:

1: Sort based on name; 2: Then sort based on age; 3: Then sort by score. The priority is that name > age > score. If the following tuples are given as input to the program: Tom,19,80 John,20,90 Jony,17,91 Jony,17,93 Json,21,85 Then, the output of the program should be: [('John', '20', '90'), ('Jony', '17', '91'), ('Jony', '17', '93'), ('Json', '21', '85'), ('Tom', '19', '80')]

My code:

info = input()
info_list = [(name, age, height) for name, age, height in 
case.split(',') for case in info.split(' ')] 
sorted(info_list, key = lambda name:name[0])

The error I got was: ValueError: too many values to unpack (expected 3)

Can anyone please help?

Answer 1

The solution would be:

info = input()
info_list = [case.split(',') for case in info.split(' ')] 
print(sorted(info_list))

Example output:

Tom,19,80 John,20,90 Jony,17,91 Jony,17,93 Json,21,85
[['John', '20', '90'], ['Jony', '17', '91'], ['Jony', '17', '93'], ['Json', '21', '85'], ['Tom', '19', '80']]

And to explain why your code doesn't work is:

• Using multiple iterators, only works for a sequence of sequences, whereas just one sequence won't work.

• Why doesn't it work with a sequence, it will try to unpack the singular element, ie 1 , which can't be unpacked as it isn't an iterable with 3 elements, that's the main reason it works for ie [1, 2, 3] .

Answer 2

Use key to sorted to specify the base of your sort.

s = 'Tom,19,80 John,20,90 Jony,17,91 Jony,17,93 Json,21,85'

lst = [tuple(x.split(',')) for x in s.split()]

print(sorted(lst, key=lambda x: (x[0], x[1], x[2])))
# [('John', '20', '90'), ('Jony', '17', '91'), ('Jony', '17', '93'), ('Json', '21', '85'), ('Tom', '19', '80')]                                      [Program finished]

where s is your input string.