如何更改列表列表中嵌套数据框的列名

Question

I have a list of data frames, the names of which are shown below:

lapply(L2, function(x) {print(names(x))}):

$D1
[1] "TP1.adjPVal" "TP1.Log2FC" 

$D2
[1] "TP2.adjPVal" "TP2.Log2FC" 

$D3
[1] "TP3.adjPVal" "TP3.Log2FC" 

$D7
[1] "TP7.adjPVal" "TP7.Log2FC" 

$D14
[1] "TP14.adjPVal" "TP14.Log2FC" 

I would like to change all the TP into D .

I have tried the following codes from searching stackoverflow but am struggling to reach my goal.

lapply(L2, function(x) {gsub(x = names(x), pattern = 'TP', replacement = 'D')})

setNames(L2$D1, tp$D1)

lapply(L2, function(x) { colnames(x) <- gsub(x = colnames(x), pattern = 'TP', replacement = 'D')})

Any help in this issue would be most welcome.

Answer 1

We need to return the x ie the data.frame. In the OP's code, it is only doing the assignment. Also, as the 'TP' is at the start of the string, can use ^ to specify the start and we don't need gsub instead use sub (for single substitution)

lapply(L2, function(x) {
       colnames(x) <- sub(x = colnames(x), pattern = '^TP', replacement = 'D')
      x}
       )

---

Or another option is setNames . In this case, we can do the assignment on the fly as setNames internally does the assignment

lapply(L2, function(x) setNames(x, 
        sub(x = colnames(x), pattern = '^TP', replacement = 'D')))

---

Also, if we use tidyverse

library(tidyverse)
map(L2, ~ .x %>%
            rename_at(vars(starts_with("TP")), ~ str_replace(., "^TP", "D")))