如何将xml文件转换为用java编写的javascript文件的xml？

Question

I have got two XML files from two different databases, but they has got the same infos. One of them has got VSReports and the other Jasperreports(JavaScript). I has to convert the XML file from VSReports into the Jasperreports. The only programming language I am allowed to use is java.

I am already stucked when I try to read in a xml file with my code.

    import javax.swing.*;
    import java.io.IOException;
    import java.nio.charset.Charset;
    import java.nio.file.Files;
    import java.nio.file.Path;
    import java.nio.file.Paths;

    public class InputBox {
        public static void main(String[] args) {
            Pfad();
        }
    //opens JFileChooser
        public static void Pfad() {

                JFileChooser chooser = new JFileChooser();
                int rueckgabeWert = chooser.showOpenDialog(null);

                if (rueckgabeWert == JFileChooser.APPROVE_OPTION) {
                    System.out.println("Die zu öffnende Datei ist: "
                            + chooser.getSelectedFile().getName());
                }

                Path path = Paths.get(chooser.getSelectedFile().getName());
            String content = null;
            try {
                content = Files.readString(path, Charset.defaultCharset());
            } catch (IOException e) {
                e.printStackTrace();
            }
//System.out.println the content of the file
            System.out.println(content);
        }
    }

It works really fine with a txt file, but when I try a XML file it comes to a error:

java.nio.file.NoSuchFileException: 123.xml
    at java.base/sun.nio.fs.WindowsException.translateToIOException(WindowsException.java:85)
    at java.base/sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:103)
    at java.base/sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:108)
    at java.base/sun.nio.fs.WindowsFileSystemProvider.newByteChannel(WindowsFileSystemProvider.java:231)
    at java.base/java.nio.file.Files.newByteChannel(Files.java:370)
    at java.base/java.nio.file.Files.newByteChannel(Files.java:421)
    at java.base/java.nio.file.Files.readAllBytes(Files.java:3205)
    at java.base/java.nio.file.Files.readString(Files.java:3283)
    at InputBox.Pfad(InputBox.java:26)
    at InputBox.main(InputBox.java:10)
null

Answer 1

你试图打开一个文件而不给它一个绝对路径，只有当文件在当前工作目录中时它才会工作

Answer 2

Based on your description, it seems you didn't pass the full name of the xml file to your function. So try

    File f = chooser.getSelectedFile();
    String path = f.getAbsolutePath + f.getName();
    try {
            content = Files.readString(path, Charset.defaultCharset());
        } catch (IOException e) {
            e.printStackTrace();
        }

Hope this help.

Answer 3

As said, File#getName() loses the directory part of the path, so it will only find a file if it is in the current directory. To convert a File object to a Path , just use its toPath() method:

Path path = chooser.getSelectedFile().toPath();