如何在Python中将字符串的每个字符转换为list元素的各个元素？

Question

How can I convert a given string's individual characters into individual elements of a list in Python? 如何在Python中将给定字符串的单个字符转换为列表的单个元素？

b = []
a = "golf"
for i in a:
    print(i)
    b.append(i)

I expect an output as: 我期望输出为：

b = ['g','o','l','f']

but the actual output is 但实际输出是

g
o
l
f

Answer 1

a = "golf"
b = list(a)
print (b)

simple as that. 就那么简单。

Answer 2

I expect an output as: 我期望输出为：

b = ['g','o','l','f'] b = ['g'，'o'，'l'，'f']

That's what you'd get if you tried (after the loop): 如果尝试过（循环之后），这就是您得到的：

print("b = {}".format(b))

but since there's no such thing in your code, there's no reason it should be printed... 但是因为您的代码中没有这样的东西，所以没有理由应该打印它。

but the actual output is 但实际输出是

g G

o Ø

l 升

f F

Well yes, that's what you asked for: 是的，这就是您要的：

# ...
for i in a:
    print(i) # <- HERE
    # ...

Answer 3

Maybe you can try this: 也许您可以尝试以下方法：

b = []
a = "golf"
for i in a:
    b.append(i)
b

The expected output will be: 预期的输出将是：

['g','o','l','f']

Or: 要么：

b = []
a = "golf"
for i in a:
    b.append(i)
print("b = {}".format(b))

and you will get this output: 您将获得以下输出：

b = ['g','o','l','f']