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如何有效地从“ dist”距离矩阵中提取行或列

[英]How to efficiently extract a row or column from a “dist” distance matrix

I'm working with a 39000+ data points and I'm computing the distance between a point and every single other one of them, resulting in a (39000+)^2 matrix that consumes 11GB (and I can't allocate this in the memory). 我正在使用39000+个数据点,并且正在计算一个点与每个其他点之间的距离,导致(39000 +)^ 2矩阵消耗11GB(而我无法在其中分配记忆)。

Great thing we have the dist function that allows me to reduce this to a little bit less than 6GB. 很棒的事情是,我们具有dist函数,该函数可使我将其减少到不到6GB。 But now, I need to calculate the inverse distances powered by 2 and then regularize every row so that they sum up to 1. This is necessary because I will later multiply every row of the matrix by a vector and store this result. 但是现在,我需要计算由2乘以的逆距离,然后对每一行进行正则化,使它们的总和为1。这是必要的,因为稍后我将矩阵的每一行乘以一个向量并将其存储。 So, the big matrix is actually a temporary thing. 因此,大矩阵实际上是暂时的。

My question is, how can I extract rows of this dist matrix? 我的问题是,如何提取此dist矩阵的行?

A sample "dist" matrix obtained with dist(cbind(runif(5),runif(5)) dist(cbind(runif(5),runif(5))获得的样本“ dist”矩阵

       1    2    3    4    
2   0.47                                                                                                                                  
3   0.63 0.72                                                                                                                             
4   0.79 0.62 0.37                                                                                                                        
5   0.53 0.15 0.62 0.48                                                                                                                   


What I'm looking for is to extract the entire first line, for instance: 我正在寻找的是提取整个第一行,例如:

0  0.47  0.63  0.79  0.53

Resort to function f in my old answer here . 我的旧答案中求助于 f

f <- function (i, j, dist_obj) {
  if (!inherits(dist_obj, "dist")) stop("please provide a 'dist' object")
  n <- attr(dist_obj, "Size")
  valid <- (i >= 1) & (j >= 1) & (i > j) & (i <= n) & (j <= n)
  k <- (2 * n - j) * (j - 1) / 2 + (i - j)
  k[!valid] <- NA_real_
  k
  }

A helper function to extract a single row / column (a slice). 提取单个行/列(切片)的辅助函数。

SliceExtract_dist <- function (dist_obj, k) {
  if (length(k) > 1) stop("The function is not 'vectorized'!")
  n <- attr(dist_obj, "Size")
  if (k < 1 || k > n) stop("k out of bound!")
  ##
  i <- 1:(k - 1)
  j <- rep.int(k, k - 1)
  v1 <- dist_obj[f(j, i, dist_obj)]
  ## 
  i <- (k + 1):n
  j <- rep.int(k, n - k)
  v2 <- dist_obj[f(i, j, dist_obj)]
  ## 
  c(v1, 0, v2)
  }

Example

set.seed(0)
( d <- dist(cbind(runif(5),runif(5))) )
#          1         2         3         4
#2 0.9401067                              
#3 0.9095143 0.1162289                    
#4 0.5618382 0.3884722 0.3476762          
#5 0.4275871 0.6968296 0.6220650 0.3368478

SliceExtract_dist(d, 1)
#[1] 0.0000000 0.9401067 0.9095143 0.5618382 0.4275871

SliceExtract_dist(d, 2)
#[1] 0.9401067 0.0000000 0.1162289 0.3884722 0.6968296

SliceExtract_dist(d, 3)
#[1] 0.9095143 0.1162289 0.0000000 0.3476762 0.6220650

SliceExtract_dist(d, 4)
#[1] 0.5618382 0.3884722 0.3476762 0.0000000 0.3368478

SliceExtract_dist(d, 5)
#[1] 0.4275871 0.6968296 0.6220650 0.3368478 0.0000000

Sanity check 完整性检查

as.matrix(d)
#          1         2         3         4         5
#1 0.0000000 0.9401067 0.9095143 0.5618382 0.4275871
#2 0.9401067 0.0000000 0.1162289 0.3884722 0.6968296
#3 0.9095143 0.1162289 0.0000000 0.3476762 0.6220650
#4 0.5618382 0.3884722 0.3476762 0.0000000 0.3368478
#5 0.4275871 0.6968296 0.6220650 0.3368478 0.0000000

Note: Function to extract diagonals readily exists. 注意: 存在提取对角线的功能。

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