小数点后只需要两位数

Question

I have string with below format

const number = "21708.333333333336"

Then I pass it to the function to get the number in this format

"21,708.333333333336"

Function I am using for to do this (I have tried this)

let numberFormat = (x) => {
  return x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ',')
}

But I need only last 2 digits

"21,708.33"

What should be the regex for this?

Answer 1

Try toLocaleString()

 let result = Number("21708.333333333336").toLocaleString(undefined, { minimumFractionDigits: 2, maximumFractionDigits: 2 }) console.log(result) 

Answer 2

Before passing it to function which convert it to string use

function numberWithCommas(x) {
    return x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
}

let number = "21708234234324.333333333336"

number = Number(number).toFixed(2);

numberWithCommas(number);

Answer 3

Try this code with basic funtionality

const number = "21708.333333333336"
function splitValue(value, index) {
    return parseInt(value.substring(0, index)) + "," + calc(value.substring(index));
}
function calc(theform) {
    var with2Decimals = theform.toString().match(/^-?\d+(?:\.\d{0,2})?/)[0]
    return parseInt(with2Decimals);
}
var val = splitValue(number, 2);
console.log(val)