与子构造函数同名的继承类成员

Question

Consider this example:

    class Label{
    public:
        std::string Text;    
    };

    class Text:
        public Label
    {
    public:
        Text(std::string text) {}
    };

    int main()
    {
        Text text("");
        text.Text; //<---- GCC CE: Invalid use of 'class Text'
        return 0;
    }

    class Text:
        public Label
    {
    public:
        Text(std::string text) {}
        using Label::Text; // doesn't help either
    };

How could one access inherited class member if it has the same name as child class?

    class Text:
        public Label
    {
    public:
        Text(std::string text):
            Text::Text(Label::Text){}
        std::string &Text;
    };

Could something like this work? (I know that code above does not.)

Answer 1

Here's a workaroud (which is quit confusing); you can access data member of base class via the base class name. eg

text.Label::Text;

Answer 2

Despite the fact that the right answer is (posted by @songyuanyao)

text.Label::Text;

I have figured out how to avoid this kinda odd syntax.

Simple "hack" with old C-style typedef will do the trick:

    typedef class Text_:
        public Label
    {
    public:
        Text_(std::string text){}
    }Text;

And now suddenly code example compiles. Woah ... C++ magic ...