[英]How to run a command using System.Diagnostics.Process?
What is wrong with this code to run a command in command prompt? 在命令提示符下运行命令的这段代码有什么问题? I try to run this code and it does not give any error and it does not do what it is supposed to do.
我尝试运行此代码,它没有给出任何错误,并且没有执行应有的功能。 It works fine if I copy the command to command prompt and run it manually?
如果我将命令复制到命令提示符并手动运行,它会很好地工作吗?
Thank you! 谢谢!
[TestMethod]
public void TestProcess()
{
string command1 = @"sejda-console simplesplit --files -f C:\TestFiles\test.pdf -o C:\TestFiles\split1\ -s all";
ProcessStartInfo processInfo;
Process process;
//I have the batch file sejda-console in C:\sejda-console-3.2.83\bin so I concatenated the directory of the batch file with the actual command.
processInfo = new ProcessStartInfo("cmd.exe", @"C:\sejda-console-3.2.83\bin " + command1);
processInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
process = Process.Start(processInfo);
process.WaitForExit();
process.Close();
}
Alternatively, I am trying this one too which does not work either. 或者,我也尝试这种方法,也不起作用。
[TestMethod]
public void TestProcess3()
{
string MyBatchFile = @"C:\sejda-console-3.2.83\bin\sejda-console.bat";
string _sourcePath = @"C:\TestFiles\test.pdf";
string _targetPath = @"C:\TestFiles\split1\";
var process = new Process
{
StartInfo = {
Arguments = String.Format("/C simplesplit --files -f {0} -o {1} -s all", _sourcePath, _targetPath)
}
};
process.StartInfo.FileName = MyBatchFile;
bool b = process.Start();
}
So your code should look like: 因此,您的代码应如下所示:
[TestMethod]
public void TestProcess()
{
string command1 = @"sejda-console simplesplit --files -f C:\TestFiles\test.pdf -o C:\TestFiles\split1\ -s all";
ProcessStartInfo processInfo;
Process process;
//I have the batch file sejda-console in C:\sejda-console-3.2.83\bin so I concatenated the directory of the batch file with the actual command.
processInfo = new ProcessStartInfo("cmd.exe", @"/C \"C:\sejda-console-3.2.83\bin\" + command1 + "\"");
processInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
process = Process.Start(processInfo);
process.WaitForExit();
process.Close();
}
Try this processInfo
: 试试这个
processInfo
:
var batch = "sejda-console.bat";
var sourcePath = @"C:\TestFiles\test.pdf";
var targetPath = @"C:\TestFiles\split1\";
var processInfo = new ProcessStartInfo();
processInfo.WorkingDirectory = @"C:\sejda-console-3.2.83\bin";
processInfo.FileName = "cmd.exe";
processInfo.Arguments = $"/C {batch} simplesplit --files -f \"{sourcePath}\" -o \"{targetPath}\" -s all";
// todo set windows style etc
Also have a look at Executing Batch File in C# for error handling. 另请参阅在C#中执行批处理文件以进行错误处理。
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