为什么if ... else语句未正确定义“结果”变量？

Question

I wish to define the variable 'result' with an if-else statement.

// These variables will be used to test my if statement: 
var a = 10;
var b = 20;

// My if if statement here: 
var result; 
if (a < b) {   
    console.log('a is smaller'); 
} else {
    console.log('a is not smaller'); 
}

// This will log my result to the console: 
console.log(result);

My if-else statement is executing correctly, but I am having trouble defining the 'result' variable.

Answer 1

Assign the string to result then log at the end.

var result;

if (a < b) {
  result = "a is smaller";
}
else {
  result = "a is not smaller";
}

console.log(result);

You could also use a ternary operator and template literal for conciseness:

var result = `a is ${a < b ? "" : "not "}smaller`;
console.log(result);

Answer 2

Try

var a = 10; var b = 20;
var result; 
if (a < b) {
    result = 'a is smaller';
} else { 
    result = 'a is not smaller'; 
}
console.log(result);

Or simply

var a = 10; var b = 20;
var result = a < b ?  'a is smaller' : 'a is not smaller'; 
console.log(result);

Or this if you want to just print

var a = 10; var b = 20;
console.log(a < b ?  'a is smaller' : 'a is not smaller');