正则表达式捕获单词后跟一个数字作为一个组

Question

I need to match this string:

Cattle: Sheep: Pigs: 
Meat –0 days Meat – 0 days Meat – 0 days
Milk – 0 hours Milk – 0 hours

To create the following capture groups:

[cattle:, sheep:, pigs:]
[meat - 0 days, meat - 0 days, meat - 0 days]
[milk - 0 days, milk - 0 days]

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I've tried to have a go myself but I am getting nowhere, I currently have something like this but it matches digits and spaces all over the string

(?!Cattle|Sheep|Pigs)(\b[Meat\s-\s\d*]\b)

I am capturing the cattle, speed and pigs strings in a different regex, hence the neg lookahead.

EDIT: Sorry I should have specific more. These are all on a separate line split into an array.

Answer 1

str =<<END
Cattle: Sheep: Pigs: 
Meat –0 days Meat – 0 days Meat – 0 days
Milk – 0 hours Milk – 0 hours
END

str.each_line.map { |line| line.chomp.downcase.split(/(?<=:|days|hours) */) }
  #=> [["cattle:", "sheep:", "pigs:"],
  #    ["meat –0 days", "meat – 0 days", "meat – 0 days"],
  #    ["milk – 0 hours", "milk – 0 hours"]]

The regular expression reads, "match one or more spaces that are immediately preceded by a colon, the word 'days' or the word 'hours', (?<=:|days|hours) being a positive lookbehind .