python-使用带有or子句的列表理解

Question

So I'm trying to convert a dictionary into a list, and at the same time I want to get the keys that do not contain certain keywords. I tried doing something like this(see below) but it doesn't seem to work. Anyone have any ideas how to do this?

[(key,value) for key, value in album.items() if ('available_markets' not in key) or ('images' not in key)]

EDIT: album data should look something like this:

album ={'album_group': 'album', 'album_type': 'album', 'artists_0_external_urls_spotify': 'https://open.spotify.com/artist/3WrFJ7ztbogyGnTHbHJFl2', 'artists_0_href': 'https://api.spotify.com/v1/artists/3WrFJ7ztbogyGnTHbHJFl2', 'artists_0_id': '3WrFJ7ztbogyGnTHbHJFl2', 'artists_0_name': 'The Beatles', 'artists_0_type': 'artist', 'artists_0_uri': 'spotify:artist:3WrFJ7ztbogyGnTHbHJFl2', 'available_markets_0': 'AD', 'available_markets_1': 'AE', 'images_1_width': 300, 'images_2_height': 64, 'images_2_url': 'https://i.scdn.co/image/f6e12b2ef70abf43d110e5c79810655c7c3fae98', 'images_2_width': 64, 'name': 'The Beatles', 'release_date': '2018-11-09', 'release_date_precision': 'day'}

My attempt returned to me:

[('album_group', 'album'), ('album_type', 'album'), 
 ('artists_0_external_urls_spotify',
  'https://open.spotify.com/artist/3WrFJ7ztbogyGnTHbHJFl2'),
 ('artists_0_href',
  'https://api.spotify.com/v1/artists/3WrFJ7ztbogyGnTHbHJFl2'),
 ('artists_0_id', '3WrFJ7ztbogyGnTHbHJFl2'),
 ('artists_0_name', 'The Beatles'),
 ('artists_0_type', 'artist'),
 ('artists_0_uri', 'spotify:artist:3WrFJ7ztbogyGnTHbHJFl2'),
 ('available_markets_0', 'AD'),
 ('available_markets_1', 'AE'),
 ('images_1_width', 300),
 ('images_2_height', 64),
 ('images_2_url',
  'https://i.scdn.co/image/f6e12b2ef70abf43d110e5c79810655c7c3fae98'),
 ('images_2_width', 64),
 ('name', 'The Beatles'),
 ('release_date', '2018-11-09'),
 ('release_date_precision', 'day')]

I shorten the album dict but available markets can be a range from 1 to 70+ and images can be from 1 to 3. I'm just trying to filter out those keys in the new list.

Answer 1

Wrap the whole operation in not instead of each individual part:

[kv for kv in album.items()
 if not ('available_markets' in key or 'images' in key)]

Alternatively, use and :

[kv for kv in album.items()
 if 'available_markets' not in key and 'images' not in key]

Thank you to @chepner for pointing out the use of and when combining negative tests.