如何使用WHERE子句在分区上进行RANK（）

Question

I need to do 2 ranks in a table, one for all rows and one where Total Cum Production is greater than zero. Is there any way to do that with a Rank Function?

SELECT 
       LocationNumber
      ,[Date]
      ,Oil+Gas+Water as [TotalFluid]
      ,sum(Oil + Gas + Water ) over (partition by [LocationNumber] order by [Date] asc) as [CumTotalFluid]
      ,rank() over (partition by [LocationNumber] order by [Date] asc) as TABLE_DAY
      ,rank() over (partition by [LocationNumber] order by [Date] asc WHERE CumTotalFluid > 0) as Prod_DAY

FROM DV

Answer 1

You can use conditional logic:

SELECT LocationNumber, [Date], (Oil+Gas+Water) as [TotalFluid],
       sum(Oil + Gas + Water ) over (partition by [LocationNumber] order by [Date] asc) as [CumTotalFluid],
       rank() over (partition by [LocationNumber] order by [Date] asc) as TABLE_DAY
       (CASE WHEN CumTotalFluid > 0
             THEN rank() over (partition by [LocationNumber], CASE WHEN CumTotalFluid > 0 THEN 1 ELSE 0 END order by [Date] asc
                              ) 
        END) as Prod_DAY
FROM DV;

The outer case only returns values where the condition is true. The case in the partition by divides the data into two (more) sets, so the ranking is correct.