[英]Remove characters from NSString?
NSString *myString = @"A B C D E F G";
我想删除空格,所以新字符串将是“ABCDEFG”。
You could use: 你可以使用:
NSString *stringWithoutSpaces = [myString
stringByReplacingOccurrencesOfString:@" " withString:@""];
If you want to support more than one space at a time, or support any whitespace, you can do this: 如果要一次支持多个空格,或者支持任何空格,可以执行以下操作:
NSString* noSpaces =
[[myString componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]
componentsJoinedByString:@""];
All above will works fine. 以上所有都可行。 But the right method is this: 但正确的方法是这样的:
yourString = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
It will work like a TRIM method. 它将像TRIM方法一样工作。 It will remove all front and back spaces. 它将删除所有前后空间。
Thanks 谢谢
Taken from NSString 取自NSString
stringByReplacingOccurrencesOfString:withString:
Returns a new string in which all occurrences of a target string in the receiver are replaced by another given string. 返回一个新字符串,其中接收器中所有出现的目标字符串都被另一个给定字符串替换。
- (NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement
Parameters 参数
target 目标
The string to replace.
replacement 替换
The string with which to replace target.
Return Value 回报价值
A new string in which all occurrences of target in the receiver are replaced by replacement. 一个新字符串,其中接收器中所有出现的目标都被替换替换。
if the string is mutable , then you can transform it in place using this form: 如果字符串是可变的 ,那么您可以使用以下形式将其转换为适当的位置:
[string replaceOccurrencesOfString:@" "
withString:@""
options:0
range:NSMakeRange(0, string.length)];
this is also useful if you would like the result to be a mutable instance of an input string: 如果您希望结果是输入字符串的可变实例,这也很有用:
NSMutableString * string = [concreteString mutableCopy];
[string replaceOccurrencesOfString:@" "
withString:@""
options:0
range:NSMakeRange(0, string.length)];
You can try this 你可以试试这个
- (NSString *)stripRemoveSpaceFrom:(NSString *)str {
while ([str rangeOfString:@" "].location != NSNotFound) {
str = [str stringByReplacingOccurrencesOfString:@" " withString:@""];
}
return str;
}
Hope this will help you out. 希望这会帮助你。
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