如何格式化json转储

Question

I got json dumps like this:

"aaa": {
    "bbb": {
        "ccc": {
            "ddd": "string1",
            "eee": "string2"
        }
    },
    "kkk": "string3"
}

And I'd like to format it this way: enclose every key-value pair (separated by : ) with {} and then replace : with , .

I know that I can use re.sub() to replace string patterns, but regular expression does not work with overlapping patterns, so I can match, for example, "ddd": "string1" but not "ccc": {...} at the same time .

For the above json string, I'd like to get:

{"aaa", {
    {"bbb", {
        {"ccc", {
            {"ddd", "string1"},
            {"eee", "string2"}
        }}
    }},
    {"kkk", "string3"}
}}

Answer 1

Here's a hack which converts everything to lists and then changes square brackets to curly ones. If your strings might contain square brackets that'll be a problem.

import json

inp = """
{
    "aaa": {
        "bbb": {
            "ccc": {
                "ddd": "string1",
                "eee": "string2"
            }
        },
        "kkk": "string3"
    }
}
"""

inp = json.loads(inp)


def items(d):
    if isinstance(d, dict):
        return [(k, items(v)) for k, v in d.items()]
    return d


inp = items(inp)

print(json.dumps(inp, indent=2).replace("[", "{").replace("]", "}"))

Output:

{
  {
    "aaa",
    {
      {
        "bbb",
        {
          {
            "ccc",
            {
              {
                "ddd",
                "string1"
              },
              {
                "eee",
                "string2"
              }
            }
          }
        }
      },
      {
        "kkk",
        "string3"
      }
    }
  }
}

Answer 2

Note that you are treating dictionary keys as ordered when they aren't, so I made it more explicit with lists.

If it were me, I wouldn't dump to JSON in the first place, I'd serialize the native python data structure straight to C++ initializer list syntax:

myobj = {
  "aaa": [
    { "bbb": {
        "ccc": [
            {"ddd": "string1"},
            {"eee": "string2"}
        ]
    }},
    { "kkk": "string3" }
  ]
}

def pyToCpp(value, key=None):
  if key:
    return '{{ "{}", {} }}'.format(key, pyToCpp(value))
  if type(value) == dict:
    for k, v in value.items():
      return pyToCpp(v, k)
  elif type(value) == list:
    l = [pyToCpp(v) for v in value]
    return '{{ {} }}'.format(", ".join(l))
  else:
    return '"{}"'.format(value)

y = pyToCpp(myobj)
print(y)

Output:

{ "aaa", { { "bbb", { "ccc", { { "ddd", "string1" }, { "eee", "string2" } } } }, { "kkk", "string3" } } }

Run it here: https://repl.it/repls/OddFrontUsers