如何在我的Makefile中包含目录及其所有子目录的标题？

Question

My project organization is as follows:

• Makefile
• build
  • objects
  • apps
• include
  • subdirectory (contains *.h)
  • subdirectory (contains *.h)
• src
  • subdirectory (contains *.cpp)
  • subdirectory (contains *.cpp)

In my makefile, to grab all *.h from the subdirectories I currently use:

#includes (.h / .hpp)
INC_DIRS := \
$(wildcard include/*/)

INCLUDE = $(foreach d, $(INC_DIRS), -I$d)

This does work, and I am able to compile fine. However I was wondering if there was a simpler way to include all subdirectories in a single include statement.

The current method I am using does a '-Iinclude/subdirectory' for each subdirectory and it looks really messy and confusing in the terminal.

Answer 1

Given your include path approach, this is a good way to specify it in your makefile.

However, it would be better to not require all these subdirectories to be in the path, and instead use relative paths inside your code.

#include "somedir/thing.h"
#include "somedir2/otherthing.h"

and so forth.

This will also then be much easier to port to other build systems if needed.