[英]How to Take custom inputs
The first line contain two separated integer N and M. Where N stands for Number of Buildings and M stands for Roads. 第一行包含两个分开的整数N和M。其中N代表建筑物数量,M代表道路。
Next follows M line, each lines consists of 4 integers IJKL representing Floor of Building, Windows in building,Time taken to climb the building, Time taken to cross road. 接下来的M行,每行由4个整数IJKL组成,分别代表建筑物的楼层,建筑物中的Windows,爬建筑物所需的时间,过马路所需的时间。
I have been able to taken the first input as follows: 我已经能够接受如下的第一个输入:
Scanner sc = new Scanner(System.in);
System.out.println("Enter N and M");
String NandM = sc.nextLine();
String [] NandMAsArray = NandM.split(" ");
int N = Integer.parseInt(NandMAsArray[0]);
int M = Integer.parseInt(NandMAsArray[1]);
I am struck while taking input for second part , which will consist of a loop of M time and taking 4 inputs each time, IJKL
respectively. 我在输入第二部分时感到震惊,这将包括一个M时间循环,每次输入4次输入,分别是IJKL
。
How do i do this?? 我该怎么做呢??
input and output for second part should be like this: 第二部分的输入和输出应如下所示:
Input: 输入:
Road:0
12 34 44 56
Road:1
22 76 89 90
https://i.postimg.cc/28fQ3dVR/Screenshot-20190807-121551-Chrome.jpg https://i.postimg.cc/28fQ3dVR/Screenshot-20190807-121551-Chrome.jpg
for (int i = 0; i < M; i++) {
int I = sc.nextInt();
int J = sc.nextInt();
int K = sc.nextInt():
int L = sc.nextInt();
// your code here
}
Since the input is constant, you can just take in the numbers directly. 由于输入是恒定的,因此您可以直接输入数字。
I am struck while taking input for second part , which will consist of a loop of M time and taking 4 inputs each time, IJKL respectively 我在输入第二部分时感到震惊,这将包括M次循环并每次输入4次输入,分别为IJKL
Based on your requirement I'd suggest you create a class rather than using primitive types. 根据您的要求,建议您创建一个类,而不要使用原始类型。 This will be easier than making a 2D array and you can do more with data. 这将比制作2D数组容易,而且您可以处理更多数据。
Since I don't exactly know the problem I am gonna assume that (Floor of Building, Windows in building,Time taken to climb the building, Time taken to cross road) all are properties of road. 由于我不完全了解问题,因此我将假定(建筑物地板,建筑物中的Windows,爬建筑物所需的时间,过马路所需的时间)都是道路的属性。 If not then you can same thing to buildings and move the attributes from road to building 如果不是,那么您可以对建筑物进行相同操作,并将属性从道路移动到建筑物
Road Class 道路等级
public class Road {
private int floorsOfBuilding;
private int windowsInBuilding;
private int climbTime;
private int crossingTime;
// Constructor
public Road(int floorsOfBuilding, int windowsInBuilding, int climbTime, int crossingTime) {
this.floorsOfBuilding = floorsOfBuilding;
this.windowsInBuilding = windowsInBuilding;
this.climbTime = climbTime;
this.crossingTime = crossingTime;
// You can do simple calculations here but for more complex it is better
// to create a method to maintain readability
}
public String toString() {
return "\n" + floorsOfBuilding + " " + windowsInBuilding + " " + climbTime + " " + crossingTime;
}
}
Main Class 主班
int roadsCount = Integer.parseInt(buildingsAndRoadsArray[1]);
Road[] roadsArray = new Road[roadsCount];
for (int i = 0; i < roadsArray.length; i++) {
System.out.println();
System.out.println("Road:" + i);
System.out.print("Enter I J K L: ");
String input = scan.nextLine();
String[] inputSplit = input.split(" ");
Road road = new Road(Integer.parseInt(inputSplit[0]), Integer.parseInt(inputSplit[1]),
Integer.parseInt(inputSplit[2]), Integer.parseInt(inputSplit[3]));
roadsArray[i] = road;
}
scan.close();
System.out.println();
for (int i = 0; i < roadsArray.length; i++) {
System.out.println("Road: " + i + roadsArray[i] + "\n");
}
Output 输出量
Enter Number of Buildings and Roads: 1 2
// Input
Road:0
Enter I J K L: 12 13 14 15
Road:1
Enter I J K L: 49 59 69 79
// Output
Road: 0
12 13 14 15
Road: 1
49 59 69 79
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