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如何向量化长度-频率计算?

[英]How to vectorize length-frequency calculation?

At the moment I have a quite long code with a for loop calculating the frequency of the various lengths at different maturities of a dataset, I would like to vectorize the code/find a more elegant solution, however so far I've not been able to work out how to do that. 目前,我有一个很长的代码,带有for循环,用于计算数据集不同成熟度下各种长度的频率,我想对代码进行矢量化处理/找到更优雅的解决方案,但是到目前为止,我还无法找出如何做到这一点。 The frequency calculation is a relatively simple one: (count of occurances of a specific length at a certain maturity/total number of females or males)*100 频率计算是一个相对简单的计算:( (count of occurances of a specific length at a certain maturity/total number of females or males)*100

Example data: 示例数据:

   Species Sex Maturity    Length
1     HAK   M        1         7
2     HAK   M        2         24
3     HAK   F        2         10
4     HAK   M        3         25
5     HAK   F        5         25
6     HAK   F        4         12

Code that I'm currently using: 我当前正在使用的代码:

reps <- seq(min(Length), max(Length), by = 1)
m1      <- m2 <- m3 <- m4 <- m5 <- rep(NA, length(reps))
f1      <- f2 <- f3 <- f4 <- f5 <- rep(NA, length(reps))
# Makes vectors for each maturity stage for both sexes 
# same length as the reps vector filled with NA for the loop:
# Loop:

for (i in 1:length(reps)) # repeats for each value of the x axis

{

        m1[i]<- length(Length[Length == reps[i] & Sex == "M" & Maturity == 1])/total.m*100
        m2[i]<- length(Length[Length == reps[i] & Sex == "M" & Maturity == 2])/total.m*100
        m3[i]<- length(Length[Length == reps[i] & Sex == "M" & Maturity == 3])/total.m*100
        m4[i]<- length(Length[Length == reps[i] & Sex == "M" & Maturity == 4])/total.m*100
        m5[i]<- length(Length[Length == reps[i] & Sex == "M" & Maturity == 5])/total.m*100
        f1[i]<- length(Length[Length == reps[i] & Sex == "F" & Maturity == 1])/total.f*100
        f2[i]<- length(Length[Length == reps[i] & Sex == "F" & Maturity == 2])/total.f*100
        f3[i]<- length(Length[Length == reps[i] & Sex == "F" & Maturity == 3])/total.f*100
        f4[i]<- length(Length[Length == reps[i] & Sex == "F" & Maturity == 4])/total.f*100
        f5[i]<- length(Length[Length == reps[i] & Sex == "F" & Maturity == 5])/total.f*100

}
#Stitching together the output of the  loop.
males_all<-rbind(m1, m2, m3, m4, m5)
females_all<-rbind(f1, f2, f3, f4, f5)

This is the output I usually get from the loop: 这是我通常从循环中获得的输出:

 mat       X8       X9       X10       X11      X12       X14       X15
1  m1 0.104712 0.104712 0.6282723 1.3612565 1.884817 0.1047120 0.2094241
2  m2 0.000000 0.000000 0.3141361 0.8376963 2.198953 2.4083770 1.3612565
3  m3 0.000000 0.000000 0.0000000 0.0000000 0.104712 0.2094241 0.1047120
4  m4 0.000000 0.000000 0.0000000 0.0000000 0.000000 0.0000000 0.0000000
5  m5 0.000000 0.000000 0.0000000 0.0000000 0.000000 0.0000000 0.2094241

The columns after mat are the lengths, for the sake of brevity I've not included all of them, they would go up to 30 or so. mat后面的列是长度,为了简洁起见,我没有将所有列都包括在内,它们可能会增加到30左右。 The females_all looks the same, just with f1, f2 etc. in the mat column. females_all看起来相同,只是在mat列中带有f1, f2等。

Near as I can tell, this is what you want: 据我所知,这就是您想要的:

library(dplyr)
counts = count(df, Sex, Maturity, Length)
totals = count(df, Sex, name = "total")

counts = counts %>% left_join(totals) %>%
  mutate(prop = n / total)
# # Joining, by = "Sex"
# # A tibble: 6 x 6
#   Sex   Maturity Length     n total  prop
#   <fct>    <int>  <int> <int> <int> <dbl>
# 1 F            2     10     1     3 0.333
# 2 F            4     12     1     3 0.333
# 3 F            5     25     1     3 0.333
# 4 M            1      7     1     3 0.333
# 5 M            2     24     1     3 0.333
# 6 M            3     25     1     3 0.333

counts %>% select(Sex, Maturity, Length, prop) %>%
  tidyr::spread(key = Length, value = prop, fill = 0)
# # A tibble: 6 x 7
#   Sex   Maturity   `7`  `10`  `12`  `24`  `25`
#   <fct>    <int> <dbl> <dbl> <dbl> <dbl> <dbl>
# 1 F            2 0     0.333 0     0     0    
# 2 F            4 0     0     0.333 0     0    
# 3 F            5 0     0     0     0     0.333
# 4 M            1 0.333 0     0     0     0    
# 5 M            2 0     0     0     0.333 0    
# 6 M            3 0     0     0     0     0.333

Using this data: 使用此数据:

df = read.table(text = "   Species Sex Maturity    Length
1     HAK   M        1         7
2     HAK   M        2         24
3     HAK   F        2         10
4     HAK   M        3         25
5     HAK   F        5         25
6     HAK   F        4         12", header = T)

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