如何在目录中找到文件名？

Question

For example, in the path C:\\Users\\Username\\filename.txt , how would I print filename.txt ?

Here is an example of a code:

>>> x = input("Enter file path: ")
>>> Enter file path: C:\Users\Username\filename.txt
# Now print filename.txt because that is the name of the file in the variable x

Answer 1

用\\分隔路径并获得最后一个元素（应该是文件名）：

print(x.split('\\')[-1])  #  ==>  filename.txt

Answer 2

The best way to do this intelligently is with the os module.

import os 

Path = 'C:\Users\Username\filename.txt'
f_path, f_name = os.path.split(Path)

>f_name
'filename.txt'

Answer 3

Try this:

x = input("Enter file path: ")
with open(x, 'r') as f:
    print(f.read())

Answer 4

method 1, you need to know the length of the filename:

path = "C:\Users\Username\filename.txt"

file = path[-12:] # ===> filename.txt

method 2, using os.path.split:

import os

file = os.path.split(path)[1]

method 3, using str.split. You need to make sure the path is seperated by '/':

file = path.split('/')[-1]