在PowerShell中将标志从一个脚本移动到另一个脚本

Question

I have 2 powershell scripts script1.ps1 and script2.ps1 . They both contain the same parameter flag and integer parameter [int]$num, [switch]$silent = $false .

Now I call script.ps1 with parameters script.ps1 222 -silent . I want to call script2.ps1 from script1.ps1 with that flag and another integer parameter. But the only decision I found is

param([int]$num, [switch]$silent = $false)

if($silent) {
    .\script2.ps1 333 -silent 
} else {
    .\script2.ps1 333
}

Is there more brief and convenient way to send parameter flag from one script to another ?

Answer 1

Switch parameters accept boolean values, so you could do something like this:

Param(
    [int]$num,
    [Switch]$silent = $false
)

.\script2.ps1 333 -silent:$silent.IsPresent

Note that this doesn't behave exactly like a passthru. The second script in this case will always be passed the parameter -silent , just with an explicit value of $true or `$false.

If you want to not pass the parameter when your first script wasn't called with it you can't get around actually making that distinction. In that case you need something like this:

Param(
    [int]$num,
    [Switch]$silent = $false
)

$extraParams = @{}
if ($PSBoundParameters.ContainsKey('silent')) {
    $extraParams['silent'] = $silent.IsPresent
}

.\script2.ps1 333 @extraParams