用于检测未用双引号括起来的单词和字符串的正则表达式

Question

I have tried to write a regular expression for the an example code to use in grep search.

My requirement is to get string output that matches only the below

execute(any word here)

For eg.

execute(any)
execute(math)

and the results should not output

execute("any")
execute("math")

I already tried the following, but the problem with this is that it outputs everything and doesn't give me the required solution.

grep -E '^execute\(*([^)]+)*\)'

I expect my output to be execute(math) or execute(s) and not

execute("math") or execute("s")

Answer 1

Based on your limited sample data, this should work:

^execute\([a-zA-Z]+\)$

https://regex101.com/r/S4owrs/2