[英]Comparing nested lists within a parent list structure for values in specific indices in java
Given a list of lists in the following format: 给定以下格式的列表列表:
List < List < String, String, BigInteger, String, String, String, String, String, String > > rows 列表<列表<字符串,字符串,BigInteger,字符串,字符串,字符串,字符串,字符串,字符串>>行
what would be the best way to iterate through each list searching for duplicate values for [1] (string for employee ID) and [2] (big integer for account ID) indices that match any other row's values for [1] and [2] in a list 遍历每个列表的最佳方法是什么,以搜索与[1]和[2]的任何其他行的值匹配的[1](员工ID的字符串)和[2](帐户ID的大整数)索引的重复值]在列表中
so that if there are rows with duplicates of both account id's and employee id's an action can be done? 这样一来,如果有行同时存在帐户ID和员工ID的重复,可以采取措施吗?
I'm supposing I got the meaning of the structure as follows: 我想我的结构含义如下:
List< Row >
, where Row
is the class you created to manage List<String, String, BigInteger, String, String, String, String, String, String>
. List< Row >
,其中Row
是您创建的用于管理List<String, String, BigInteger, String, String, String, String, String, String>
。
In this case you could override the method equals()
in this class to match your "duplicated" values. 在这种情况下,您可以重写此类中的
equals()
方法以匹配您的“重复”值。
class Row {
...
@Override
public boolean equals(Object o) {
if (o instanceof Row) {
return account.equals(((Row)o).getAccount())
&& employee.equals((Row)o).getEmployee());
}
return false;
}
}
Then in your main list, you can apply one of the algorithms to find duplications. 然后,在您的主列表中,您可以应用一种算法来查找重复项。 As in [ https://crunchify.com/java-how-to-find-duplicate-elements-from-list/] .
如[ https://crunchify.com/java-how-to-find-duplicate-elements-from-list/]中所示 。 One example could be:
一个示例可能是:
void processDuplicates (List<Row> list) {
Set<Row> already = new HashSet<>();
for (Row row : list) {
if (already.contains(row)) {
// row is duplicated
// do something
} else {
already.add(row);
}
}
}
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