[英]shutil.move() only works with existing folder?
I would like to use the shutil.move() function to move some files which match a certain pattern to a newly created(inside python script)folder, but it seems that this function only works with existing folders.我想使用 shutil.move() 函数将一些匹配特定模式的文件移动到新创建的(在 python 脚本中)文件夹,但似乎该函数仅适用于现有文件夹。
For example, I have 'a.txt', 'b.txt', 'c.txt' in folder '/test', and I would like to create a folder '/test/b' in my python script using os.join() and move all .txt files to folder '/test/b'例如,我在文件夹“/test”中有“a.txt”、“b.txt”、“c.txt”,我想使用 os.txt 在我的 python 脚本中创建一个文件夹“/test/b”。 join() 并将所有 .txt 文件移动到文件夹 '/test/b'
import os
import shutil
import glob
files = [file for file in glob.glob('./*.txt')] #assume that we in '/test'
for f in files:
shutil.move(f, './b') #assume that './b' already exists
#the above code works as expected, but the following not:
import os
import shutil
import glob
new_dir = 'b'
parent_dir = './'
path = os.path.join(parent_dir, new_dir)
files = [file for file in glob.glob('./*.txt')]
for f in files:
shutil.move(f, path)
#After that, I got only 'b' in '/test', and 'cd b' gives:
#[Errno 20] Not a directory: 'b'
Any suggestion is appreciated!任何建议表示赞赏!
the problem is that when you create the destination path variable name:问题在于,当您创建目标路径变量名称时:
path = os.path.join(parent_dir, new_dir)
the path doesn't exist .路径不存在。 So
shutil.move
works, but not like you're expecting, rather like a standard mv
command: it moves each file to the parent directory with the name "b", overwriting each older file, leaving only the last one (very dangerous, because risk of data loss)所以
shutil.move
工作,但不像你期望的那样,而是像一个标准的mv
命令:它将每个文件移动到名为“b”的父目录,覆盖每个旧文件,只留下最后一个(非常危险,因为有数据丢失的风险)
Create the directory first if it doesn't exist:如果目录不存在,首先创建目录:
path = os.path.join(parent_dir, new_dir)
if not os.path.exists(path):
os.mkdir(path)
now shutil.move
will create files when moving to b
because b
is a directory.现在
shutil.move
将在移动到b
时创建文件,因为b
是一个目录。
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