如何避免每次回发后页面跳动？

Question

I'm using an UpdatePanel and the form auto-saves after every onTextChanged trigger. However, the page keeps going to the top. How do i keep the page where the onfocus is?

I'm currently using the MaintainScrollPositionOnPostback="true" but that's not working:

<%@ Page Title="Welcome" Language="C#" MasterPageFile="account-master.master" 
        AutoEventWireup="true" 
        CodeFile="Welcome.aspx.cs" 
        Inherits="Welcome"  
        MaintainScrollPositionOnPostback="true" 
    %>

I used the following javascript code to fix this issue:

'window.onscroll = function () {
        var scrollY = document.body.scrollTop;
        if (scrollY == 0) {
            if (window.pageYOffset) {
                scrollY = window.pageYOffset;
            }
            else {
                scrollY = (document.body.parentElement) ? document.body.parentElement.scrollTop : 0;
            }
        }
        if (scrollY > 0) {
            var input = document.getElementById("scrollY");
            if (input == null) {
                input = document.createElement("input");
                input.setAttribute("type", "hidden");
                input.setAttribute("id", "scrollY");
                input.setAttribute("name", "scrollY");
                document.forms[0].appendChild(input);
            }
            input.value = scrollY;
        }
    };'

Answer 1

This seemed to work. runs on windowload

window.onload = function () {
        var scrollY = parseInt('<%=Request.Form["scrollY"] %>');             
        if (!isNaN(scrollY)) {
            window.scrollTo(0, scrollY);
        }
    };
    window.onscroll = function () {
        var scrollY = document.body.scrollTop;
        if (scrollY == 0) {
            if (window.pageYOffset) {
                scrollY = window.pageYOffset;
            }
            else {
                scrollY = (document.body.parentElement) ? document.body.parentElement.scrollTop : 0;
            }
        }
        if (scrollY > 0) {
            var input = document.getElementById("scrollY");
            if (input == null) {
                input = document.createElement("input");
                input.setAttribute("type", "hidden");
                input.setAttribute("id", "scrollY");
                input.setAttribute("name", "scrollY");
                document.forms[0].appendChild(input);
            }
            input.value = scrollY;
        }
    };