Docker构建挂起--->运行

Question

newish to docker

I have a docker file that I run docker build on, and it looks like this, where base is an image thats running microsoft/windowsservercore:10.0.14393.2312:

FROM base
MAINTAINER Captain Adam Weitzman
SHELL ["powershell", "-Command", "$ErrorActionPreference = 'Stop'; $ProgressPreference = 'SilentlyContinue';"]

ENV NPM_VERSION=6.4.1 \
    IONIC_VERSION=3.19.0 \
    CORDOVA_VERSION=9.0.0 \
    NUGET_VERSION=4.7.0;

RUN echo hello world

with output:

Step 1/5 : FROM base
 ---> 9dbf7f740334
Step 2/5 : MAINTAINER Captain Adam Weitzman
 ---> Using cache
 ---> c8f96e0797b9
Step 3/5 : SHELL ["powershell", "-Command", "$ErrorActionPreference = 'Stop'; $ProgressPreference = 'SilentlyContinue';"]
 ---> Using cache
 ---> 769be32b31a5
Step 4/5 : ENV NPM_VERSION=6.4.1     IONIC_VERSION=3.19.0     CORDOVA_VERSION=9.0.0   NUGET_VERSION=4.7.0;
 ---> Using cache
 ---> e2005178d304
Step 5/5 : RUN apt-get update
 ---> Running in 9ddc94cf3765

It seems to just hang on the running part, and won't finish building...why? I also have a docker ignore file with ** in it...could that be a reason?

Answer 1

运行并行以将更多内存分配给我的虚拟机