如何使用python中的beautifulsoup从网页中获取数据

Question

I am trying to scrape the data from the given link bellow, a link

And I an saving it into csv file.

I got all movies name, but in other format bellow, please see bellow: I am getting bellow format in csv:

T h e " " S h a w s h a n k " " R e d e m p t i o n

T h e " " G o d f a t h e r

T h e " " G o d f a t h e r : " " P a r t " " I I

T h e " " D a r k " " K n i g h t

1 2 " " A n g r y " " M e n

S c h i n d l e r ' s " " L i s t

It should be:

The Shawshank Redemption

The Godfather

The God father: Part II

The Dark Knight

I tried:

from bs4 import BeautifulSoup
import requests
import csv

url = 'https://www.imdb.com/chart/top'
res = requests.get(url)
soup = BeautifulSoup(res.text)
movie = soup.find_all(class_='titleColumn')

for names in movie:
    for name in names.find_all('a'):
        movies=list(name.text)
        # print(movies)

        # IN CSV
        with open('TopMovies.csv', 'a') as csvFile:
            writer = csv.writer(csvFile, delimiter = ' ')
            writer.writerow(movies)
        csvFile.close()
        print(movies)

print("Successfully inserted")

Please, Let me know if its any changes in my code.

Thanks

Answer 1

Problem is in line movies=list(name.text) - you are creating list, where each item is character from the string name.text .

Instead of this list() , you can use list-comprehension movies = [name.text for name in names.find_all('a')] :

from bs4 import BeautifulSoup
import requests
import csv

url = 'https://www.imdb.com/chart/top'
res = requests.get(url)
soup = BeautifulSoup(res.text)
movie = soup.find_all(class_='titleColumn')

for names in movie:
    movies = [name.text for name in names.find_all('a')]
    # print(movies)

    # IN CSV
    with open('TopMovies.csv', 'a') as csvFile:
        writer = csv.writer(csvFile, delimiter = ' ')
        writer.writerow(movies)
    csvFile.close()
    print(movies)

print("Successfully inserted")

This will create TopMovies.csv correctly.

Screenshot from LibreOffice: