[英]After imputation, how to round to nearest level of a factor
I have imputed missing values in the following data frame in column q1. q1
我在第
q1. q1
列的以下数据框中估算了缺少的值q1. q1
q1. q1
is a factor with the levels 0,20,40,60,80,100
. q1. q1
是水平为0,20,40,60,80,100
的因子。 I need to round the column q1
to nearest level of factors, number 49 and 91
need to be rounded. 我需要将
q1
列四舍五入到最接近的因子水平,数字49 and 91
需要四舍五入。 Does anyone have a solution for this problem?, thanks in advance! 有人对此问题有解决方案吗?,谢谢!
id <- rep(c(300,450), each=6)
> visit <- rep(1:6,2)
> trt <- rep(c(0,"A",0,"B",0,"C"),2)
> q1 <- c(0,100,0,89,0, 60,0,85,0,40,0, 20)
> df <- data.frame(id,visit,trt,q1)
> df
id visit trt q1
1 300 1 0 0
2 300 2 A 100
3 300 3 0 0
4 300 4 B 49
5 300 5 0 0
6 300 6 C 60
7 450 1 0 0
8 450 2 A 91
9 450 3 0 0
10 450 4 B 40
11 450 5 0 0
12 450 6 C 20
>
Maybe you could use plyr
's round_any
function here which would round to nearest multiple of 20 in this case. 也许您可以在此处使用
plyr
的round_any
函数,在这种情况下,该函数将舍入到最接近的20的倍数。
plyr::round_any(df$q1, 20)
#[1] 0 100 0 80 0 60 0 80 0 40 0 20
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