使用Xslt转换Xml

Question

I have the following XML:

<?xml version="1.0" encoding="utf-8" ?>
 <ApplicationSettingCategories>
 <Category>Cat1</Category>
 <Category>Cat2</Category>
 <Category>Cat3</Category>
 <Category>Cat4</Category>
 <Category>Cat5</Category>
 <Category>Cat6</Category>
</ApplicationSettingCategories>

I am trying to bind this Xml to a Dropdownlist in ASP.net using an XmlDataSource and Xslt. This is my first time doing this. The Dropdownlist shows the correct number of blank items, leading me to believe the iteration is working but the Values and Text are blank.

Any help in identifying my error would be appreciated.

Thanks

My XLST

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="ApplicationSettingCategories">
    <Categories>
        <xsl:apply-templates select="Category"/>
    </Categories>
</xsl:template>

<xsl:template match="Category">
    <Category>
        <xsl:attribute name="Category">
            <xsl:value-of select="Category"/>
        </xsl:attribute>
    </Category>
</xsl:template>

My ASPX

<asp:DropDownList ID="ddl1" runat="server" DataSourceID="XmlDataSource1" 
DataTextField="Category" DataValueField="Category" />
    <asp:XmlDataSource ID="XmlDataSource1" runat="server" 
    DataFile="~/App_Data/Xml/SettingCategory.xml" 
    TransformFile="~/Schema/AppCategoryXSLT.xslt"></asp:XmlDataSource>

My Source View

<select name="ddl1" id="ddl1">
<option value=""></option>
<option value=""></option>
<option value=""></option>
<option value=""></option>
<option value=""></option>
<option value=""></option>
</select>

Answer 1

This line is your problem:

<xsl:value-of select="Category"/>

At this point (inside the Category template), the context node is the current category. The selector you have on your xsl:value-of is looking for a child element of the context node also called Category . Just change that line to get the context node's text value instead:

<xsl:value-of select="text()"/>