[英]how to calculate elapsed time in days and hours
Hi everyone I have two columns in datetime format and I want to make a new column with the elapsed time in days and a second column containing the rest in hours. 大家好,我有两列为datetime格式,我想创建一个新列,以天为单位经过时间,第二列以小时为单位包含其余时间。 please see the exemple: 请参见示例:
my data : 我的数据:
# importing pandas as pd
import pandas as pd
# creating a dataframe
df = pd.DataFrame({'DATE_IDENTIFIED': ['2019-06-27 10:42:50 ', '2019-06-28 13:11:58', '2019-06-20 13:12:23','2019-06-26 11:14:59','2019-06-26 11:16:04'],
'DATE_CLOSED': ['2019-09-27 10:40:38', '2019-06-28 19:11:22',
'2019-06-28 18:11:22','2019-06-26 13:13:38','2019-06-28 14:15:37']})
DATE_IDENTIFIED DATE_CLOSED
0 2019-06-27 10:42:50 2019-06-27 10:40:38
1 2019-06-28 13:11:58 2019-06-28 13:11:22
2 2019-06-28 13:12:23 2019-06-28 13:11:22
3 2019-06-26 11:14:59 2019-06-26 11:13:38
4 2019-06-26 11:16:04 2019-06-26 11:15:37
Example 例
DATE_IDENTIFIED DATE_CLOSED days hours
2019-06-27 10:42:50 2019-09-27 10:40:38 90 0
2019-06-28 13:11:58 2019-06-28 19:11:22 0 6
2019-06-20 13:12:23 2019-06-28 18:11:22 8 5
2019-06-26 11:14:59 2019-06-26 13:13:38 0 2
2019-06-26 11:16:04 2019-06-28 14:15:37 2 3
Perhaps something along the line of the code in this post might get you started: 也许这篇文章中的代码可能会使您入门:
df['A'] = pd.to_datetime(df['A'])
df['B'] = pd.to_datetime(df['B'])
df['C'] = (df['B'] - df['A']).dt.days
For the remaining hours you might need to do some additional math by for instance converting the difference in hours and subtracting the number of days times 24 hours 对于剩余的小时数,您可能需要做一些额外的数学运算,例如转换小时数之差并减去24小时的天数
df['B'] = (df['B'] - df['A']).dt.hours - df['C'] * 24
You need to do: 您需要做:
### first convert your columns to datetime object if it is not already
df['DATE_IDENTIFIED'] = pd.to_datetime(df['DATE_IDENTIFIED'])
df['DATE_CLOSED'] = pd.to_datetime(df['DATE_CLOSED'])
### GET DAYS LIKE THIS
df['days'] = (df['DATE_CLOSED'] - df['DATE_IDENTIFIED']).dt.days
### GET HOURS LIKE THIS
df['hours'] = df['DATE_CLOSED'].dt.hour - df['DATE_IDENTIFIED'].dt.hour
Output: 输出:
DATE_IDENTIFIED DATE_CLOSED days hours
0 2019-06-27 10:42:50 2019-09-27 10:40:38 91 0
1 2019-06-28 13:11:58 2019-06-28 19:11:22 0 6
2 2019-06-20 13:12:23 2019-06-28 18:11:22 8 5
3 2019-06-26 11:14:59 2019-06-26 13:13:38 0 2
4 2019-06-26 11:16:04 2019-06-28 14:15:37 2 3
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