[英]remove fill color levels from a ggplotly legend
Is there a way to remove the fill color from the ggplotly
legend since it is redundant with the facet?有没有办法从
ggplotly
图例中删除填充颜色,因为它与刻面是多余的? In other words, it's true that I essentially have four combinations, but I only want to show the levels of alpha in the legend because the faceting tells you the same information as the fill values.换句话说,我确实有四种组合,但我只想在图例中显示 alpha 的级别,因为分面告诉您与填充值相同的信息。 I don't need to explain what red and green mean since red only applies to facet
group3==0
and green only applies to facet group3==1
.我不需要解释红色和绿色的含义,因为红色只适用于 facet
group3==0
而绿色只适用于 facet group3==1
。
---
title: "Example"
runtime: shiny
output:
flexdashboard::flex_dashboard:
vertical_layout: fill
---
```{r}
library(tidyverse)
library(plotly)
library(flexdashboard)
```
### Chart 1
```{r}
f <- list(family = "Poppins")
a <- list(tickfont = f)
p <- fortify(forecast::gold) %>%
mutate(group1 = sample(0:1, n(), replace=TRUE),
group2 = sample(0:1, n(), replace=TRUE),
group3 = sample(0:1, n(), replace=TRUE)
) %>%
ggplot(., aes(factor(group1), y, alpha=factor(group2), fill=factor(group3))) +
geom_col() +
scale_alpha_manual(values = c(.5, 1)) +
facet_wrap(~group3)
ggplotly(p)
```
I arrived here from google because a ggplot that didn't have a legend was being given one when ggplotly()
was called on it.我从谷歌来到这里是因为当
ggplotly()
时,给出了一个没有图例的ggplotly()
。
In case that affects anyone else, the answer is, use:如果影响其他人,答案是,使用:
theme(legend.position='none')
as plotly understands that.正如情节理解的那样。
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