[英]Extracting non-null portion of pandas series from DataFrame
Say I have this DataFrame: 说我有这个DataFrame:
C1 C2 C3
0 1 4.4 99
1 2 4.5 200
2 3 NaN 65
3 4 3.2 140
I want to extract only the column (series) C2 and only the non-null elements of that series. 我只想提取C2列(系列),而只提取该系列的非null元素。
I can do that in two steps: 我可以分两个步骤进行操作:
d = df.loc[df['C2'].notnull()]
s=d['C2']
s will be s将是
0 4.4
1 4.5
3 3.2
Can I do this in one step? 我可以一步一步完成吗?
You are talking about dropna
您在谈论
dropna
df.C2.dropna()
Out[486]:
0 4.4
1 4.5
3 3.2
Name: C2, dtype: float64
Consider using query
with .notna
if you want to filter your dataframe: 如果要过滤数据
.notna
,请考虑对.notna
使用query
:
df.query('C2.notna()')
Output 输出量
C1 C2 C3
0 1 4.4 99
1 2 4.5 200
3 4 3.2 140
您也可以将两个步骤组合为一个步骤并放下位置
df[df['C2'].notnull()]['C2']
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.