如何从字符串中提取单个电子邮件地址？

Question

I need to extract a single email address from this kind of string.

Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details

const string = "Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details";
const mailMatch = string.match(/(\S+@[^\s.]+\.{1}[^.]\S+)/);

The match in this case will be this `

[0: "example@gmail.com."
1: "example@gmail.com."
groups: undefined
index: 79
input: "Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details"
length: 2]

I don't want to match the dot(indicating end of the sentence) at the end of mail. How to change my regexp , in order to get only example@gmail.com

Answer 1

You may use

 var string = "Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details"; var mailMatch = string.match(/\\S+@[^\\s.]+\\.[^.\\s]+/); console.log(mailMatch); // => Matched text: example@gmail.com // Or, if you may have any non-whitespace chars and you want to stop at the last console.log( "The example@site.co.uk address is not available".match(/\\S+@[^\\s.]+\\.\\S+\\b/) ); // => Matched text: example@site.co.uk // Or just console.log( "The example@some.site.co.uk address is not available".match(/\\S+@\\S+\\.\\S+\\b/) ); // => Matched text: example@some.site.co.uk

Since it is not quite clear what email requirements you have a more generic example would be

s.match(/\S+@\S+\.\S+\b/)

Details

• \\S+ - 1+ non-whitespace chars
• @ - a @ char
• \\S+ - 1+ non-whitespace chars
• \\. - a dot
• \\S+\\b - 1+ non-whitespace chars that end with a word boundary.

If you need to extract valid looking emails only here is a solution with a bit amended well-known email validation regex:

 var email_rx_extract = /(?:[^<>()[\\]\\\\.,;:\\s@"]+(?:\\.[^<>()[\\]\\\\.,;:\\s@"]+)*|".+")@(?:\\[\\d{1,3}(?:\\.\\d{1,3}){3}]|(?:[a-zA-Z0-9-]+\\.)+[a-zA-Z]{2,})(?![a-zA-Z])/g; var s = "The example@some.site.co.uk address is not available\\nBad email is example@gmail...........com."; var results = s.match(email_rx_extract); console.log(results); // => Only example@some.site.co.uk is found.